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w^2+5w-1800=0
a = 1; b = 5; c = -1800;
Δ = b2-4ac
Δ = 52-4·1·(-1800)
Δ = 7225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7225}=85$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-85}{2*1}=\frac{-90}{2} =-45 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+85}{2*1}=\frac{80}{2} =40 $
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